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(325x^2+50)/4=7
We move all terms to the left:
(325x^2+50)/4-(7)=0
We multiply all the terms by the denominator
(325x^2+50)-7*4=0
We add all the numbers together, and all the variables
(325x^2+50)-28=0
We get rid of parentheses
325x^2+50-28=0
We add all the numbers together, and all the variables
325x^2+22=0
a = 325; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·325·22
Δ = -28600
Delta is less than zero, so there is no solution for the equation
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